Problem:
Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.
Given linked list -- head = [4,5,1,9], which looks like following:
Example 1:
Input: head = [4,5,1,9], node = 5
Output: [4,1,9]
Explanation: You are given the second node with value 5, the linked list should become 4 -> 1 -> 9 after calling your function.
Example 2:
Input: head = [4,5,1,9], node = 1
Output: [4,5,9]
Explanation: You are given the third node with value 1, the linked list should become 4 -> 5 -> 9 after calling your function.
-Summary-
1. Change current node's value to the next node value.
2. Change current node's next direction to next next.
Leetcode에 있는 discussion 에서의 그래픽이 이해하는데 도움이 된다.
leetcode.com/problems/delete-node-in-a-linked-list/discuss/354949/Python3-1-line-with-explanation
class Solution(object):
def deleteNode(self, node):
"""
1 -> 2 -> 3 -> 4
^ ^
| |
node node.next
______________
/ \
1 -> 3 3 4
^ ^ ^
| | |
node node.next node.next.next
______________
/ \
1 -> 3 3 4
^ ^ ^
| | |
node node.next node.next.next
1 ->3 ->4
"""
node.val , node.next = node.next.val, node.next.next
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